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i think u got it. reguardless,i wouldnt want to be a half mile, quarter mile or 105' from the impact of that shellOh snap.. I did it too.
42,000 / 100 = 420
420 * 3 = 1260
1260 / 12 = 105'
Right?
The last part is obvious,but I think these guns were much better than that ,no?I think we are both wrong.
1"@ 100 yards so 4200" @ 42,000 yards so 350 feet, I had one too many zeros in my head
Aren't there a few islands in the Pacific full of these things?So how do you get one of these? Well it was pretty simple back in the day. You looked for the 20 foot crater in the foot hills outside of town and you dug till you hit metal. They guy my dad got this one from dug up three, the other two are the posts for his front gate.
I get the impression the OP's projectile is a training load - no explosive. Which is why it's still intact. Those found in the beaches of Pacific islands.......... I'm no chemist or explosives expert, but even after almost 3/4s of a century, I wouldn't want to dig one of those bad boys up.
There are three kinds of people in this world; those who can do math, and those who cant.i can see where im wrong now that i read my calculations. i said yards not inches lol and i still was wrong. pffff MATH.
And those that know MOA to be 1.047"@ 100 yards. That doesn't matter at 100 yards, but at 42,000 it could make a bit of difference.There are three kinds of people in this world; those who can do math, and those who cant.
Heck of a charge behind that thing too.
One of my great uncles was served in a 16" gun crew, powder handler. In one of his stories, he said that those guns would get shot out and the accuracy would degrade, so to compensate they would cut in a extra 1-3 sacks of powder and the difference was, apparently, pretty noticeable.