I recently was given a box of federal 357 mag jacketed lead bullets. The box says 495 energy foot pounds at 25 yards and 1190 fps velocity. It seems that the bullet accelerates from zero and reaches peak velocity either inside the barrel or at the muzzel (MV is 1240) Then as it loses velocity over range the EFP gradually decreases until it reaches zero again as the bullet comes to rest. My question is, what consideration is given to the area of the point of empact of the traveling mass on the stationary object it collides with? It would seem that the wider the nose area of the bullet the kinetic energy would be distributed over a wider area of the object it collides with. Am I correct in concluding that the shock a bullet provides is related not only to the velocity and mass of the bullet but also to the size of the area of impact. (Not taking into consideration that bullets are designed to cause mechanical damage as well.) When a bullet mushrooms upon impact the kinetic energy of the bullet is distributed over a wider area. The bullet has less penetration over a wider area and more shock value than a pointed bullet that retains it's kinetic energy as it passes through an object. Does a lead wadcutter have more shock value than a lead round point of the same weight and velocity?