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Yeabut what if you're on a treadmill and the world is round?An object in motion tends to stay in motion... then there's that gravity thing, not to mention friction.
Round? Pa-shaw. Everyone knows the world is flat...Yeabut what if you're on a treadmill and the world is round?
Bullets can't go up before they go down *unl asylum(WTF? Unless you?)* are pointing the barrel in an upward direction. So if using sights,scopes whatever,if you are aiming horizontally,your barrel is pointed up a little if you have the scope dialed in at say 100 yardsWell, from my research, most bullets don't travel in a truly horizontal path, then tend to go up a bit after being fired, then drop as air friction and gravity act on them. Obviously there are a lot of factors: barrel length, powder charge, bullet weight, bullet design, environmental factors such as altitude, wind, even temperature and humidity.
But if you want to get a snapshot view of how they react under certain circumstances, the table at this link might be helpful:
Handgun Trajectory Table
Bullets can't go up before they go down unl asylum are pointing the barrel in an upward direction. So if using sights,scopes whatever,if you are aiming horizontally,your barrel is pointed up a little if you have the scope dialed in at say 100 yards
As to the question at hand,if a 22 round will travel a mile,given all the variances of weight,drag,energy and such, I would guess most center fire rounds would come close to that.
That's having a looong stretch with no traffic and loving a shot at say 45*?
My best guess
Yes it's a controlled environment...if I'm floating in space (you know, as one normally does), will the primer ignite the powder in the cartridge?
...if I'm floating in space (you know, as one normally does), will the primer ignite the powder in the cartridge?
Here is info from a guy much smarter than I when someone on the 1911 forum asked the same question
Assume 850 feet per second (259.08 meters/sec) fired from 6 feet high.
-1.828 m = 0 + .5(-9.81 m/s^2)t^2
t = .611 s
x = vxt = (259.08 m/s)(.611 s) = 519.217 feet
Now, assume it was fired 45 degrees up from parallel with the ground. This would give the most possible range.
vix = vi cos 45* = 183.197 m/s
viy = vi sin 45* = 183.197 m/s
0 = 183.197 m/s + .5(-9.81)t
t = 37.349 s
(183.197 m/s)(37.349 s) = 6,842.23 m = 22,442 ft
Of course, these equations do not take into account form drag or skin friction drag. Therefore, actual numbers will be lower.
That's deadly range,not how far the bullet will actually travelIf you watch some of the YouTube guys videos when they shoot pistols long range 300+ yards, they generally will say they are aiming 20 feet above the target (as an example - caliber and distance will vary), but that's an extreme range for a .45acp.
I think Iraqveteran8888 did a 9mm test and found it was (if you can hit your target) only in the deadly range out to 400 yards.
.45's with the much heavier bullet and smaller velocity would be well under that in my guestimation.
The angle of the dangle is determined by the heat of the meat.