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Could someone with access to a Smith & Wesson 686 revolver please measure the legth of their cylinder?

Has this length changed over the years with the different dash-something model numbers?

Thank you,

Neven
 
Thank you Valzey.

Adding at least 0.06 inches for the rim thickness, this means that the max C.O.L. for any 686 is at least 1.620 + 0.060 = 1.680'' or around 5.6% higher than the standard 357 mag COL of 1.590'' (5.6% more energy with the same max pressure if loaded to use the full cylinder).

I would appreciate it if someone could make the same measurement on the Ruger GP-100.
 
My estimate for the extra energy based on a quick calculation of extra powder volume above was much too conservative. Here is a more accurate calculation based on the reported 686 cylinder length of 1.620'' and my calculated max COL of 1.680'', in case someone else may be interested.

- 180 grain hard cast lead bullet 0.75'' long,
- a standard length 357 cartridge 1.59'' long leaves
1.59'' - 0.75'' - 0.06'' =0.78'' for the powder.
mbcStriker357.jpg

S&W 686 MAX COL = 1.68''
this is 1.68''-1.59''= 0.09'' longer than 1.59''
leaving an extra 0.09'' for the powder.

The relative increase of available volume for the powder
delta_V/V = 0.09/0.78 = 11.5%

This is a significant increase in available volume.
For example, 13.5 grains MAX of Hodgdon H110 becomes
13.5 * 1.115 = 15 grains MAX with the same powder density = same max pressure.
 
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